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In the system X+2YhArrZ, the equilibrium...

In the system `X+2YhArrZ`, the equilibrium concentration are,
`[X]=0.06" mol L"^(-1),[Y]=0.12" mol L"^(-1)`,
`[Z]=0.216" mol L"^(-1)`. Find the equilibrium constant of the reaction.

A

`120`

B

`400`

C

`4xx10^(-3)`

D

`250`

Text Solution

Verified by Experts

The correct Answer is:
D
`A+2BhArrC`
`K=([C])/([A][B]^(2))rArr ((0.216))/((0.06)(0.012)^(2))=250`
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