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At equilibrium the concentrations of N(2...

At equilibrium the concentrations of `N_(2) = 3.0 xx 10^(-3)M, O_(2) = 4.2 xx 10^(-3) M` and `NO = 2.8 xx 10^(-3) M` ina sealed vessel at `800 K`. What will be `K_(c)` for the reaction
`N_(2)(g) + O_(2)(h) hArr 2NO(g)`

Text Solution

Verified by Experts

For the reaction equilibrium constant `K_(c )` can be written as
`K_(c )=([NO]^(2))/([N_(2)][O_(2)])=((2.8xx10^(-3)M)^(2))/((3.0xx10^(-3)M)(4.2xx10^(-3)M))=0.622`
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