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Solid NH(4)HS(s) (ammonium hydrogen sulp...

Solid `NH_(4)HS(s)` (ammonium hydrogen sulphate) dissociates to give `NH_(3)(g)` and `H_(2)S(g)` and is allowed to attain equilibrium at `100^(@)C`. If the value of `K_(p)` for its dissociation is found to be `0.34`, find the total pressure at equilibrium at `100^(@)C`. If the value of `K_(p)` for its dissociation is found to be `0.34`, find the total pressure at equilibrium and partial pressure of each component.

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To solve the problem, we need to analyze the dissociation of solid ammonium hydrogen sulfate (NH₄HS) into ammonia (NH₃) and hydrogen sulfide (H₂S) gases. The equilibrium reaction can be represented as follows: \[ \text{NH}_4\text{HS}(s) \rightleftharpoons \text{NH}_3(g) + \text{H}_2\text{S}(g) \] Given that the equilibrium constant \( K_p \) for this reaction at 100°C is 0.34, we will find the total pressure at equilibrium and the partial pressures of each gas. ### Step 1: Set Up the Initial Conditions Assume we start with 1 mole of NH₄HS. At the beginning (before dissociation), we have: ...
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