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The degree of dissociation of HI at a pa...

The degree of dissociation of `HI` at a particualr temperature is `0.8`. Calculate the volume of `2 M Na_(2)S_(2)O_(3)` solution required to neutralise the iodine present in an equilibrium mixture of a reaction when 2 mol each of `H_(2)` and `I_(2)` are heated in a closed vessel of `2 L` capacity and the equilibrium mixture is freezed.

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To solve the problem step by step, we will follow the outlined approach to find the volume of 2 M Na₂S₂O₃ solution required to neutralize the iodine present in the equilibrium mixture. ### Step 1: Calculate the Equilibrium Constant (Kc) for the Dissociation of HI The dissociation reaction of HI can be represented as: \[ 2 \text{HI} \rightleftharpoons \text{H}_2 + \text{I}_2 \] Given that the degree of dissociation (α) of HI is 0.8, we can set up the equilibrium concentrations. Initially, we have 2 moles of HI in a 2 L vessel, so the initial concentration of HI is: ...
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