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The equilibrium constant K(p) for the re...

The equilibrium constant `K_(p)` for the reaction,
`N_(2)+3H_(2) hArr 2NH_(3)`
is `1.64xx10^(-4)` at `400^(@)C` and `0.144xx10^(-4)` at `500^(@)C`. Calculate the mean heat of formation of `1` mol of `NH_(3)` from its elements in this temperature range.

Text Solution

AI Generated Solution

To calculate the mean heat of formation of 1 mole of NH₃ from its elements in the given temperature range, we will follow these steps: ### Step 1: Convert Temperatures to Kelvin We need to convert the given temperatures from Celsius to Kelvin using the formula: \[ T(K) = T(°C) + 273.15 \] - For \( 400°C \): \[ T_1 = 400 + 273.15 = 673.15 \, K \] ...
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