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A schematic plot of log K(eq) vs inverse...

A schematic plot of log `K_(eq)` vs inverse of temperature for a reaction is shown in the figure. The reaction must be:

A

Exothermic

B

Endothermic

C

One with negligible enthalpy change

D

Highly spontaneous at ordinary temperature

Text Solution

Verified by Experts

`K_(c )=Ae^(-DeltaH^(ɵ)//RT)`
`log_(10) K_(eq)=log_(10)A-(DeltaH^(ɵ))/(2.303RT)`
`Y=C+MX`
Slope of the line will be positive, when `DeltaH^(ɵ)= -ve`, i.e. the reaction is xeothermic.
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