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At 448^(@)C, the equilibrium constant (K...

At `448^(@)C`, the equilibrium constant `(K_(c))` for the reaction
`H_(2)(g)+I_(2)(g) hArr 2HI(g)`
is `50.5`. Predict the direction in which the reaction will proceed to reach equilibrium at `448^(@)C`, if we start with `2.0xx10^(-2)` mol of HI, `1.0xx10^(-2)` mol of `H_(2)` and `3.0xx10^(-2)` mol of `I_(2)` in a `2.0 L` container.

Text Solution

AI Generated Solution

To solve the problem, we need to determine the direction in which the reaction will proceed to reach equilibrium based on the given concentrations and the equilibrium constant \( K_c \). ### Step-by-Step Solution: 1. **Write the Balanced Equation**: The balanced equation for the reaction is: \[ H_2(g) + I_2(g) \rightleftharpoons 2HI(g) ...
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