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0.5 mol of H(2) and 0.5 mol of I(2) reac...

`0.5 mol` of `H_(2)` and `0.5` mol of `I_(2)` react in `10 L` flask at `448^(@)C`. The equilibrium constant `(K_(c ))` is `50` for
`H_(2)+I_(2) hArr 2HI`
a. What is the value of `K_(p)`?
b. Calculate the moles of `I_(2)` at equilibrium.

Text Solution

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To solve the problem step by step, we will address each part of the question systematically. ### Part a: Finding the value of Kp 1. **Understand the reaction and given data**: - The reaction is: \[ H_2 + I_2 \rightleftharpoons 2 HI ...
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