Home
Class 11
CHEMISTRY
K(c ) for CO(g)+H(2)O(g) hArr CO(2)(g)+H...

`K_(c )` for `CO(g)+H_(2)O(g) hArr CO_(2)(g)+H_(2)(g)` at `986^(@)C` is `0.63`. A mixture of `1` mol `H_(2)O(g)` and `3` mol `CO (g)` is allowed to react to come to an equilibrium. The equilibrium pressure is `2.0` atm.
a. How many moles of `H_(2)` are present at equilibrium ?
b. Calculate partial pressure of each gas at equilibrium.

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the given reaction and the equilibrium conditions. ### Given Reaction: \[ \text{CO(g)} + \text{H}_2\text{O(g)} \rightleftharpoons \text{CO}_2(g) + \text{H}_2(g) \] ### Given Data: - \( K_c = 0.63 \) at \( 986^\circ C \) - Initial moles of \( \text{H}_2\text{O} = 1 \, \text{mol} \) ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Concept Applicationexercise 7.1|53 Videos
  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 7.2|40 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|15 Videos
  • CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Analytical and Descriptive Type|3 Videos

Similar Questions

Explore conceptually related problems

For the reaction CO(g)+H_(2)O(g) hArr CO_(2)(g)+H_(2)(g) at a given temperature, the equilibrium amount of CO_(2)(g) can be increased by

For the equilibrium H_(2) O (1) hArr H_(2) O (g) at 1 atm 298 K

In the reaction : C(s)+CO2(g)⇌2CO(g) , the equilibrium pressure is 6 atm. If 50% of CO2 reacts, then Kp of the reaction is

A sample of HI(g) is placed in flask at a pressure of 0.2 atm . At equilibrium. The partial pressure of HI(g) is 0.04 atm . What is K_(p) for the given equilibrium? 2HI(g) hArr H_(2)(g)+I_(2)(g)

A sample of HI(g) is placed in flask at a pressure of 0.2 atm . At equilibrium. The partial pressure of HI(g) is 0.04 atm . What is K_(p) for the given equilibrium? 2HI(g) hArr H_(2)(g)+I_(2)(g)

At 700 K, CO_(2) and H_(2) react to form CO and H_(2)O . For this purpose, K_(c ) is 0.11 . If a mixture of 0.45 mol of CO_(2) and 0.45 mol of H_(2) is heated to 700 K . (a) Find out amount of each gas at equilibrium. (b) When equilibrium has been reached, another 0.34 mol of CO_(2) and 0.34 mol of H_(2) are added to the reaction mixture. Find the composition of of mixture at new equilibrium.

In the reaction C(s)+CO_(2)(g) hArr 2CO(g) , the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(p) .

N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) for the reaction initially the mole ratio was 1: 3 of N_(2). H_(2) . At equilibrium 50% of each has reacted. If the equilibrium pressure is p, the partial pressure of NH_(3) at equilibrium is

For the reaction C(s) +CO_(2)(g) rarr 2CO(g) , k_(p)=63 atm at 100 K. If at equilibrium p_(CO)=10p_(CO_(2)) then the total pressure of the gases at equilibrium is

For the reaction C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63 atm at 100 K. If at equilibrium p_(CO)=10p_(CO_(2)) then the total pressure of the gases at equilibrium is