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At some temperature and under a pressure...

At some temperature and under a pressure of `4` atm, `PCl_(5)` is `10%` dissociated. Calculated the pressure at which `PCl_(5)` will be `20%` dissociated temperature remaining same.

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To solve the problem of calculating the pressure at which \( PCl_5 \) will be 20% dissociated, we can follow these steps: ### Step 1: Understand the dissociation of \( PCl_5 \) The dissociation of \( PCl_5 \) can be represented as: \[ PCl_5 \rightleftharpoons PCl_3 + Cl_2 \] ...
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