Home
Class 11
CHEMISTRY
One "mole" of N(2) is mixed with three m...

One "mole" of `N_(2)` is mixed with three moles of `H_(2)` in a `4L` vessel. If `0.25% N_(2)` is coverted into `NH_(3)` by the reaction
`N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g)`, calculate `K_(c)`. Also report `K_(c)` for
`1/2 N_(2)(g)+3/2 H_(2)(g) hArr NH_(3)(g)`

Text Solution

AI Generated Solution

To solve the problem step by step, we will follow the reaction and the information provided in the question. ### Step 1: Write the balanced chemical equation The balanced chemical equation for the reaction is: \[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \] ### Step 2: Determine initial moles We start with: ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Concept Applicationexercise 7.1|53 Videos

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 7.2|40 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|15 Videos

  • CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Analytical and Descriptive Type|3 Videos

Similar Questions

Explore conceptually related problems

For the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?

For the reaction, N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , the units of K_(p) are …………

One mole of N_(2) (g) is mixed with 2 moles of H_(2)(g) in a 4 litre vessel If 50% of N_(2) (g) is converted to NH_(3) (g) by the following reaction : N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) What will the value of K_(c) for the following equilibrium ? NH_(3)(g)hArr(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g)

For the reactions, N_2(g) + 3H_2(g) hArr 2NH_3(g), " " K_p=K_c (RT)^(…..)

2 mol of N_(2) is mixed with 6 mol of H_(2) in a closed vessel of one litre capacity. If 50% N_(2) is converted into NH_(3) at equilibrium, the value of K_(c) for the reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g)

1 mol of N_(2) is mixed with 3 mol of H_(2) in a litre container. If 50% of N_(2) is converted into ammonia by the reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , then the total number of moles of gas at the equilibrium are

For the reaction, N_2[g] + 3H_2[g] hArr 2NH_3[g] , Delta H = …

Which of the following is correct for the reaction? N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g)

In the reaction N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g) , the value of the equlibrium constant depends on

For the reaction N_(2)(g) + 3H_(2)(g) rarr 2NH_(2)(g) Which of the following is correct?