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Some solid NH(4)HS is placed in flask co...

Some solid `NH_(4)HS` is placed in flask containing `0.5` atm of `NH_(3)`. What would be the pressure of `NH_(3)` and `H_(2)S` when equilibrium is reached.
`NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(p)=0.11`

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AI Generated Solution

To solve the problem, we need to analyze the equilibrium reaction and use the equilibrium constant \( K_p \) to find the pressures of \( NH_3 \) and \( H_2S \) at equilibrium. ### Step-by-Step Solution: 1. **Write the Equilibrium Reaction:** The reaction is given as: \[ NH_4HS(s) \rightleftharpoons NH_3(g) + H_2S(g) ...
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