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When C(2)H(5)OH and CH(3)COOH are mixed ...

When `C_(2)H_(5)OH` and `CH_(3)COOH` are mixed in equivalent proportion, equilibrium is reached when `2//3` of acid and alcohol are used. How much ester will be present when `2g` "mole"cule of acid were to react with `2g` "mole"cule of alcohol.

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To solve the problem, we will follow these steps: ### Step 1: Identify the Reaction The reaction between ethanol (C₂H₅OH) and acetic acid (CH₃COOH) can be represented as: \[ \text{C}_2\text{H}_5\text{OH} + \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COOC}_2\text{H}_5 + \text{H}_2\text{O} \] This is an esterification reaction where ethanol and acetic acid react to form ethyl acetate (the ester) and water. ### Step 2: Determine Initial Moles ...
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