Home
Class 11
CHEMISTRY
Calculate K(c ) for the reaction KI+I(2)...

Calculate `K_(c )` for the reaction `KI+I_(2) hArr KI_(3)`. Given that initial weight of `KI` is `1.326 g` weight of `KI_(3)` is `0.105 g` and number of moles of free `I_(2)` is `0.0025` at equilibrium the volume of solution is `1L`.

Text Solution

AI Generated Solution

To calculate the equilibrium constant \( K_c \) for the reaction \[ \text{KI} + \text{I}_2 \rightleftharpoons \text{KI}_3 \] we will follow these steps: ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Concept Applicationexercise 7.1|53 Videos

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 7.2|40 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|15 Videos

  • CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Analytical and Descriptive Type|3 Videos

Similar Questions

Explore conceptually related problems

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

For the reaction 2HI(g)hArr H_(2)(g)+I_(2)(g) . The value of K_(c) is 4. If 2 moles of H_(2)," 2 moles of "I_(2) and 2 moles of HI are present in one litre container then moles of I_(2) present at equilibrium is :

The value of K_(c) for the reaction : H_(2)(g)+I_(2)(g)hArr 2HI(g) is 45.9 at 773 K. If one mole of H_(2) , two mole of I_(2) and three moles of HI are taken in a 1.0 L flask, the concentrations of HI at equilibrium at 773 K.

The value of K_(c) for the reaction: H_(2)(g)+I_(2)(g) hArr 2HI (g) is 48 at 773 K. If one mole of H_(2) , one mole of I_(2) and three moles of HI are taken in a 1L falsk, find the concentrations of I_(2) and HI at equilibrium at 773 K.

The value of K_(c) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) is 64 at 773K . If one "mole" of H_(2) , one mole of I_(2) , and three moles of HI are taken in a 1 L flask, find the concentrations of I_(2) and HI at equilibrium at 773 K .

In the reaction 2CuSO_(4)+4KI rarr 2Cu_(2)I_(2)+I_(2)+2K_(2)SO_(4) the equivalent weight of CuSO_(4) will be:

For the reaction, H_(2) + I_(2)hArr 2HI, K = 47.6 . If the initial number of moles of each reactant and product is 1 mole then at equilibrium

for the reaction 2A_((g)) hArr B_((g)) + 3C_((g)) , at a given temperature, K_(c) = 16. What must be the volume of the falsk, If a mixture of 2 mole cach A, B and C exist in equilibrium ?

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with