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Sulphide ions in alkaline solution react...

Sulphide ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equilibrium constant for the formation of `S_(2)^(2-)` and `S_(3)^(2-)` from `S` and `S^(2-)` ions is `1.7` and `5.3` respectively. Calculate equilibrium constant for the formation of `S_(3)^(2-)` from `S_(2)^(2-)` and `S`.

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To solve the problem, we need to calculate the equilibrium constant for the formation of \( S_3^{2-} \) from \( S_2^{2-} \) and \( S \). We have two equilibrium constants provided for related reactions. ### Step-by-Step Solution: 1. **Identify the Reactions and Equilibrium Constants**: - The first reaction is: \[ S + S^{2-} \rightleftharpoons S_2^{2-} ...
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