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N(2) and O(2) combine at a given tempera...

`N_(2)` and `O_(2)` combine at a given temperature to produce `NO`. At equilibrium the yield of `NO` is 'x' precent by volume. If `x=sqrt(Ka.b)-(K(a+b))/(4)`, where `K` is the equilibrium constant of the given reaction at the given temperature and `a` and `b` are the volume percentage of `N_(2)` and `O_(2)`, respectively, in the initial state. Report. Report the value of `K` at which `X` is maximum

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To solve the problem, we need to find the value of \( K \) at which the yield of \( NO \) (denoted as \( x \)) is maximized. The expression for \( x \) is given by: \[ x = \sqrt{K \cdot a \cdot b} - \frac{K \cdot (a + b)}{4} \] where \( a \) and \( b \) are the volume percentages of \( N_2 \) and \( O_2 \) respectively in the initial state. ...
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