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Calculate the equilibrium constant for the reaction
`H_(2)(g)+CO_(2)(g) hArr H_(2)O(g)+CO(g)` at `1395K`
If the equilibrium constants at `1395 K` for the following are:
`2H_(2)O(g) hArr 2H_(2)+O_(2)(g), K_(1)=2.1xx10^(-13)`
`2CO_(2)(g) hArr 2CO(g)+O_(2)(g), K_(2)=1.4xx10^(-12)`

Text Solution

Verified by Experts

`K=(K_(2)//K_(1))^(1//2)=(1.4xx10^(-12)//2.1xx10^(-13))^(1//2)`
`=(20//3)^(1//2)=2.58`
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