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For the reaction H(2)(g)+CO(2) (g)hArrC...

For the reaction
`H_(2)(g)+CO_(2) (g)hArrCO(g)+H_(2)O(g),` if the initial concentration of`[H_(2)]=[CO_(2)]`and x moles /litres of hydrogen is consumed at equilibrium , the correct expression of `K_(p)` is :

A

`x^(2)/((1-x)^(2))`

B

`((1+x)^(2))/((1-x)^(2))`

C

`(1+x^(2))/((2+x)^(2))`

D

`x^(2)/(1+x^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`{:(,H_(2)(g),+,CO_(2)(g),hArr,CO(g),+,H_(2)O(g)),(t=0,x,,x,,0,,0),(t=t_("Eq"),1-x,,1-x,,x,,x):}`
`:. K=([CO][H_(2)O])/([H_(2)][CO_(2)])=x^(2)/((1-x)^(2))`
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