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K(p)//K(c) for the reaction CO(g)+1/2 ...

`K_(p)//K_(c)` for the reaction
`CO(g)+1/2 O_(2)(g) hArr CO_(2)(g)` is

A

`RT`

B

`(RT)^(1//2)`

C

`(1)/((RT)^(3))`

D

`(1)/sqrt(RT)`

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The correct Answer is:
To find the ratio \( K_p/K_c \) for the reaction: \[ \text{CO}(g) + \frac{1}{2} \text{O}_2(g) \rightleftharpoons \text{CO}_2(g) \] we will follow these steps: ### Step 1: Identify the reaction and write the expression for \( K_c \) and \( K_p \) For the reaction: \[ \text{CO}(g) + \frac{1}{2} \text{O}_2(g) \rightleftharpoons \text{CO}_2(g) \] The equilibrium constant \( K_c \) is defined as: \[ K_c = \frac{[\text{CO}_2]}{[\text{CO}][\text{O}_2]^{1/2}} \] And the equilibrium constant \( K_p \) is defined as: \[ K_p = \frac{P_{\text{CO}_2}}{P_{\text{CO}} \cdot P_{\text{O}_2}^{1/2}} \] ### Step 2: Calculate \( \Delta n \) To relate \( K_p \) and \( K_c \), we need to calculate \( \Delta n \), which is the change in the number of moles of gas: \[ \Delta n = \text{(moles of gaseous products)} - \text{(moles of gaseous reactants)} \] In our reaction: - Moles of gaseous products = 1 (from CO₂) - Moles of gaseous reactants = 1 (from CO) + 0.5 (from O₂) = 1.5 Thus, \[ \Delta n = 1 - 1.5 = -0.5 \] ### Step 3: Relate \( K_p \) and \( K_c \) The relationship between \( K_p \) and \( K_c \) is given by the equation: \[ K_p = K_c (RT)^{\Delta n} \] Substituting \( \Delta n = -0.5 \): \[ K_p = K_c (RT)^{-0.5} = \frac{K_c}{\sqrt{RT}} \] ### Step 4: Find the ratio \( \frac{K_p}{K_c} \) Now, we can find the ratio \( \frac{K_p}{K_c} \): \[ \frac{K_p}{K_c} = \frac{1}{\sqrt{RT}} \] ### Final Answer Thus, the ratio \( K_p/K_c \) for the given reaction is: \[ \frac{K_p}{K_c} = \frac{1}{\sqrt{RT}} \]

To find the ratio \( K_p/K_c \) for the reaction: \[ \text{CO}(g) + \frac{1}{2} \text{O}_2(g) \rightleftharpoons \text{CO}_2(g) \] we will follow these steps: ...
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