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For the equilibrium AB(g) hArr A(g) +B...

For the equilibrium
`AB(g) hArr A(g) +B(g)`,
`K_(p)` is equal to four times the total pressure. Calculate the number of moles of `A` formed.

A

`0.45`

B

`0.30`

C

`0.60`

D

`0.90`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(,AB(g),hArr,A(g),+,B(g)),(underset(("moles"))(t=0),1,,0,,0),(t=t_("eq"),1-alpha,,alpha,,alpha):}`
`rArr K_(p)=(p_(A).p_(B))/P_(AB)=((alpha/(a+alpha)P)(alpha/(a+alpha)P))/((1-alpha)/(1+alpha)P)`
`rArr K_(p)=(x^(2)P)/(1-alpha^(2))=4P ("given") rArr alpha=0.9`
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