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For the reaction, PCl(3)(g)+Cl(2)(g) hAr...

For the reaction, `PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g)`, the position of equilibrium can be shifted to the right by:

A

Doubling the volume

B

Increasing the temperature

C

Addition of equimolar quantities of `PCl_(3)` and `PCl_(5)`

D

Addition of `Cl_(2)` at constant volume

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The correct Answer is:
To determine how the position of equilibrium for the reaction \( PCl_3(g) + Cl_2(g) \rightleftharpoons PCl_5(g) \) can be shifted to the right, we can analyze the factors that affect equilibrium according to Le Chatelier's principle. ### Step-by-step Solution: 1. **Understanding the Reaction**: The reaction involves the conversion of phosphorus trichloride (\( PCl_3 \)) and chlorine gas (\( Cl_2 \)) into phosphorus pentachloride (\( PCl_5 \)). The equilibrium can be affected by changes in concentration, pressure, and temperature. 2. **Applying Le Chatelier's Principle**: According to Le Chatelier's principle, if a system at equilibrium is disturbed, the system will adjust itself to counteract the disturbance and restore a new equilibrium. This means that if we increase the concentration of the reactants, the equilibrium will shift to the right to produce more products. 3. **Evaluating the Options**: - **Doubling the Volume**: This would decrease the pressure and could shift the equilibrium to the side with more moles of gas, which is not favorable for this reaction. - **Increasing the Temperature**: This reaction is exothermic (producing heat), so increasing the temperature would shift the equilibrium to the left (favoring the reactants). - **Adding Equimolar Quantities of \( PCl_3 \) and \( PCl_5 \)**: This does not change the concentration of \( Cl_2 \) and could potentially shift the equilibrium to the left or have no significant effect. - **Adding \( Cl_2 \) at Constant Volume**: This increases the concentration of one of the reactants (\( Cl_2 \)), which according to Le Chatelier's principle, will shift the equilibrium to the right to produce more \( PCl_5 \). 4. **Conclusion**: The correct way to shift the equilibrium to the right is by adding \( Cl_2 \) at constant volume. ### Final Answer: The position of equilibrium can be shifted to the right by the addition of \( Cl_2 \) at constant volume. ---
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