`N_(2)O_(4) hArr 2NO_(2), K_(c)=4`. This reversible reaction is studied graphically as shown in the figure. Select the correct statement out of `I, II` and `III`.
I : Reaction quotient has maximum value at point `A`
II : Reaction proceeds left to right at a point when `[N_(2)O_(2)]=[NO_(2)]=0.1 M`
III : `K=Q` when point `D` or `F` is reached:

Options

A. I, II
B. II, III
C. II
D. I, II, III

Answer

B

Explanation

`N_(2)O_(4)(g) hArr 2NO_(2)(g), K_(c )=4`
From graph, at point `A, Q=0`
When `[N_(2)O_(4)]=[NO(2)]=0.1 M`
`rArr Q=([NO_(2)]^(2))/([N_(2)O_(4)])=0.1 lt K_(c ) rArr ` Reaction is movind in forward direction.
At point `D` or `F[NO_(2)]` and `[N_(2)O_(4)]` is constant with time `rArr` Achivement of chemical equilibrium.