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Unit of equilibrium constant is:...

Unit of equilibrium constant is:

A

`(mol L^(-1))^(1-n)`

B

`(mol L^(-1))^(Deltan)`

C

`(atm)^(Deltan)`

D

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The correct Answer is:
To determine the unit of the equilibrium constant, we need to understand the definitions of \( K_c \) and \( K_p \) and how to calculate them based on the stoichiometry of a given chemical reaction. ### Step-by-Step Solution: 1. **Understand the Equilibrium Constant**: - The equilibrium constant \( K_c \) is used for reactions in terms of concentration (molarity), while \( K_p \) is used for reactions in terms of partial pressures. 2. **Define \( K_c \)**: - For a general reaction: \[ aA + bB \rightleftharpoons cC + dD \] - The expression for \( K_c \) is given by: \[ K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b} \] - Here, \([A]\), \([B]\), \([C]\), and \([D]\) are the molar concentrations of the reactants and products. 3. **Calculate the Change in Moles (\( \Delta n \))**: - \( \Delta n \) is defined as: \[ \Delta n = (c + d) - (a + b) \] - This represents the change in the number of moles of gaseous products minus the number of moles of gaseous reactants. 4. **Determine the Units of \( K_c \)**: - The units of \( K_c \) can be derived from the expression: \[ K_c = \frac{[\text{products}]}{[\text{reactants}]} \] - The units of concentration are moles per liter (mol/L). Therefore, the units of \( K_c \) can be expressed as: \[ K_c \text{ units} = \left( \text{mol/L} \right)^{\Delta n} = \text{mol}^{\Delta n} \cdot \text{L}^{-\Delta n} \] - This can also be written as: \[ \text{mol} \cdot \text{L}^{-1} \text{ whole}^{\Delta n} \] 5. **Define \( K_p \)**: - For the same reaction, the expression for \( K_p \) is given by: \[ K_p = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b} \] - Here, \( P \) represents the partial pressures of the gases involved in the reaction. 6. **Determine the Units of \( K_p \)**: - The units of pressure are typically in atmospheres (atm). Therefore, the units of \( K_p \) can be expressed as: \[ K_p \text{ units} = \text{atm}^{\Delta n} \] ### Summary of Units: - The unit of \( K_c \) is \( \text{mol}^{\Delta n} \cdot \text{L}^{-\Delta n} \) or \( \text{mol} \cdot \text{L}^{-1} \text{ whole}^{\Delta n} \). - The unit of \( K_p \) is \( \text{atm}^{\Delta n} \).
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CENGAGE CHEMISTRY ENGLISH-CHEMICAL EQUILIBRIUM-Exercises (Multiple Correct)
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  7. When two reactants A and B are mixed to give products C and D, the rea...

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  8. At constant temperature , the equilibrium constant (KP) for the deco...

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  9. Consider the following equilibrium in a closed container, N(2)O(4(g)...

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  10. Which of the following do not change the value of K for a reaction?

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  11. For which of the following reactions at equilibrium at constant temper...

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  12. Unit of equilibrium constant is:

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  13. Which is/are correct?

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  14. For the reaction, CaCO(3)(s) rarr CaO(s)+CO(2)(g), which is the correc...

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  15. N(2)O(2) hArr 2NO, K(1), (1/2)N(2)+(1/2)O(2) hArr NO, K(2), 2NO hA...

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  16. The rate of disappearance of A at two temperature is given by A hArr B...

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  17. Which of the following factors would favour the formation of ammonia?

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  18. Which of the following will not affect the value of equilibrium consta...

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  19. Which of the following statement is/are wrong?

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  20. When NaNO(3) is heated in a closed vessel, oxygen is liberated and NaN...

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