The vapour density of `Pcl_(5)` is `104.16` but when heated to `230^(@)C`, its vapour density is reduced to `62`. The degree of dissociation of `PCl_(5)` at `230^(@)C` is …………

Explanation

To find the degree of dissociation of PCl5 at 230°C, we can follow these steps:

### Step 1: Write the dissociation equation
The dissociation of phosphorus pentachloride (PCl5) can be represented as:
\[ \text{PCl}_5 \rightleftharpoons \text{PCl}_3 + \text{Cl}_2 \]

### Step 2: Define initial moles
Assume we start with 1 mole of PCl5. Therefore, initially:
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