Home
Class 11
CHEMISTRY
Pure ammonia is placed in a vessel at a ...

Pure ammonia is placed in a vessel at a temperature where its dissociation constant `(alpha)` is appreciable. At equilibrium,

A

`K_(p)` does not change significantly with pressure

B

`alpha` does not change with pressure

C

The concentration of `NH_(3)` does not change with pressure.

D

The concentration of hydrogen is less than that of nitrogen.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the dissociation of pure ammonia (NH₃) and its equilibrium state, we will analyze the equilibrium reaction and the implications of pressure changes on the dissociation constant (Kp) and the degree of dissociation (α). ### Step-by-Step Solution: 1. **Write the Equilibrium Reaction:** The dissociation of ammonia can be represented as: \[ 2 \text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3 \text{H}_2(g) \] 2. **Define Initial and Equilibrium Conditions:** - Initially, we have 1 mole of NH₃ and no products (N₂ and H₂). - At equilibrium, let α be the degree of dissociation of NH₃. Thus: - Moles of NH₃ at equilibrium = \(1 - \alpha\) - Moles of N₂ at equilibrium = \(\frac{\alpha}{2}\) - Moles of H₂ at equilibrium = \(\frac{3\alpha}{2}\) 3. **Write the Expression for Kp:** The equilibrium constant Kp for the reaction can be expressed in terms of partial pressures: \[ K_p = \frac{P_{N_2} \cdot P_{H_2}^3}{P_{NH_3}^2} \] Where: - \(P_{N_2} = \frac{\alpha}{2} \cdot P_{total}\) - \(P_{H_2} = \frac{3\alpha}{2} \cdot P_{total}\) - \(P_{NH_3} = (1 - \alpha) \cdot P_{total}\) 4. **Analyze the Effect of Pressure on Kp:** Kp is only a function of temperature. Although the degree of dissociation (α) changes with pressure, Kp remains constant at a given temperature. Thus: - **Statement A:** "Kp does not change significantly with pressure" is **correct**. 5. **Evaluate the Other Statements:** - **Statement B:** "α does not change with pressure" is **incorrect**. α does change with pressure to maintain the value of Kp. - **Statement C:** "The concentration of NH₃ does not change with pressure" is **incorrect**. The concentration of NH₃ changes with α, which is affected by pressure. - **Statement D:** "The concentration of hydrogen is less than that of nitrogen" is **incorrect**. From the stoichiometry of the reaction, the concentration of H₂ is greater than that of N₂. ### Conclusion: The only correct statement is A.

To solve the problem regarding the dissociation of pure ammonia (NH₃) and its equilibrium state, we will analyze the equilibrium reaction and the implications of pressure changes on the dissociation constant (Kp) and the degree of dissociation (α). ### Step-by-Step Solution: 1. **Write the Equilibrium Reaction:** The dissociation of ammonia can be represented as: \[ 2 \text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3 \text{H}_2(g) ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (Fill In The Blanks)|3 Videos
  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (True/False)|4 Videos
  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives (Multiple Correct)|6 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|15 Videos
  • CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Analytical and Descriptive Type|3 Videos

Similar Questions

Explore conceptually related problems

On doubling P and V at constant temperature, the equilibrium constant will

i. The initial pressure of PCl_(5) present in one litre vessel at 200 K is 2 atm. At equilibrium the pressure increases to 3 atm with temperature increasing to 250 . The percentage dissociation of PCl_(5) at equilibrium is

In a solid hArr liquid equilibrium , temperature remains constant.

Equilibrium constant K_(p) for the reaction CaCO_(3)(s) hArr CaO(s) + CO_2(g) is 0.82 atm at 727^@C . If 1 mole of CaCO_(3) is placed in a closed container of 20 L and heated to this temperature, what amount of CaCO_(3) would dissociate at equilibrium?

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure.

0.1 mol of PCl_(5) is vaporised in a litre vessel at 260^(@)C . Calculate the concentration of Cl_(2) at equilibrium, if the equilibrium constant for the dissociation of PCl_(5) is 0.0414 .

Two moles of NH_(3) when put into a proviously evacuated vessel (one litre) pertially dissociate into N_(2) and H_(2) . If at equilibrium one mole of NH_(3) is present, the equilibrium constant is

Consider one mole of an ideal gas whose volume changes with temeperature as V=(alpha)/(T) , where alpha is a constant. Heat is supplied to the gas to raise its temperature by DeltaT . If gamma adiabatic constant then choose the correct options.

Assertion (A) : Adding inert gas to dissociation equilibrium of N_(2)O_(4) at constant pressure and temperature increases the dissociation. Reason (R) : molar concentration of the reactants and products decreases.