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If equilibrium constant for the reactio...

If equilibrium constant for the reactions.
` A_2 +B_2 hArr 2AB,`
is K , then the backward reactions.
` AB hArr (1)/(2) A_2 + (1)/(2) B_2.`
its value is 1/K . Is it true or false? If false then write the correct constant.

Text Solution

Verified by Experts

False. If the equilibrium constant for the reaction
`AB hArr 1/2 A_(2)+1/2 B_(2)`
the equilibrium constant is `sqrt(1//K)` because the reaction is reversed as well as divided by two.
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