In the reaction of `BeF_(2)` with `2F^(Θ)` to form `BeF_(4)^(-2)`, which reactant is the Lewis acid and which is the Lewis base?

Explanation

To determine which reactant is the Lewis acid and which is the Lewis base in the reaction of `BeF2` with `2F^(-)` to form `BeF4^(2-)`, we can follow these steps:

### Step 1: Understand the definitions of Lewis acid and Lewis base
- A **Lewis acid** is a species that can accept a pair of electrons (electron pair acceptor).
- A **Lewis base** is a species that can donate a pair of electrons (electron pair donor).

### Step 2: Analyze the reactants
- The reactants in this reaction are `BeF2` and `2F^(-)`.
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