Calculate the percent error in the `[H_(3)O^(o+)]` made by neglecting the ionisation of water in `10^(-6)M NaOH` solution.

Explanation

To calculate the percent error in the \([H_3O^+]\) concentration made by neglecting the ionization of water in a \(10^{-6} M\) NaOH solution, we can follow these steps:

### Step 1: Determine the concentration of \([OH^-]\)
Since NaOH is a strong base, it completely dissociates in water. Therefore, the concentration of hydroxide ions \([OH^-]\) in the solution is equal to the concentration of NaOH:
\[ [OH^-] = 10^{-6} \, M \]

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