The self ionisation constant for pure `HCOOH, K = [HCOO overset(o+)H_(2)] [HCOO^(Θ)]` is `10^(-6)` at room temperature. What percentage of `HCOOH` molecules are converted to `HCOO^(Θ)` ions. The density of `HCOOH` iws `1.22 g cm^(-3)`.

Explanation

To solve the problem, we need to determine the percentage of `HCOOH` molecules that ionize into `HCOO^-` ions based on the given self-ionization constant and the density of `HCOOH`. Here’s a step-by-step solution:

### Step 1: Understand the Self-Ionization Reaction
The self-ionization of formic acid (`HCOOH`) can be represented as:
\[ 2 \, HCOOH \rightleftharpoons HCOO^- + HCOO^+ \]
Given that the self-ionization constant \( K \) is:
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