The solubility of `BaSO_(4)` in water is `2.33 g 100 mL^(-1)`. Calculate the percentage loss in weight when `0.2g` of `BaSO_(4)` is washed with
a. `1L` of water
b. `1L` of `0.01 NH_(2)SO_(4).[Mw_(BaSO_(4)) = 233 g mol^(-1)]`

Explanation

To solve the problem, we will break it down into two parts:

### Part A: Washing with 1 L of Water

1. **Determine the solubility of `BaSO4`:**
The solubility of `BaSO4` is given as `2.33 g/100 mL`. To convert this to grams per liter:
\[
\text{Solubility in g/L} = 2.33 \, \text{g/100 mL} \times 10 = 23.3 \, \text{g/L}
...