For the indicator 'HIn' the ratio `(Ind^(Θ))//(HIn)` is `7.0` at `pH` of `4.3`. What is `K_(eq)` for the indicator.

Explanation

To find the equilibrium constant \( K_{eq} \) for the indicator \( HIn \), we can follow these steps:

### Step 1: Understand the dissociation of the indicator
The dissociation of the indicator can be represented as:
\[ HIn \rightleftharpoons H^+ + In^- \]
Here, \( HIn \) is the undissociated form of the indicator, \( H^+ \) is the hydrogen ion, and \( In^- \) is the dissociated form.
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