`K_(sp)` of `SrF_(2) = 2.8 xx 10^(-9)` at `25^(@)C`. How much `NaF` should be added to `100mL` of solution having `0.016M` in `Sr^(2+)` ions to reduce its concentration to `2.5 xx 10^(-3)M`?

Explanation

To solve the problem, we need to determine how much sodium fluoride (NaF) should be added to a 100 mL solution containing strontium ions (Sr²⁺) to reduce its concentration from 0.016 M to 2.5 x 10⁻³ M.

### Step-by-Step Solution:

1. **Identify the Initial and Final Concentrations**:
- Initial concentration of Sr²⁺ = 0.016 M
- Final concentration of Sr²⁺ = 2.5 x 10⁻³ M

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