The vapour pressur of `0.01molal` solution of weak base `BOH` in water at `20^(@)C` is `17.536mm`. Calculate `K_(b)` for base. Aqueous tension at `20^(@)C` is `17.540mm`. Assume molality and molarity same.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Given Information
- We have a 0.01 molal solution of a weak base \( BOH \) in water.
- The vapor pressure of the solution \( P_s \) is 17.536 mm Hg.
- The vapor pressure of pure water \( P_{s}^{\circ} \) is 17.540 mm Hg.
- We will assume that molality and molarity are the same.

...