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A solution containing 10^(-3) M Sr(C1O(4...

A solution containing `10^(-3) M Sr(C1O_(4))_(2)` and `0.05 M KNO_(3)` was found to have only `75%` of its strontium in the uncomplexed `Sr^(2+)` form, the rest being `Sr(NO_(3))^(o+)`. Calcualate the `K_(1)` for complexation reaction:
`Sr^(2+) + NO_(3)^(Theta) rarr Sr (NO_(3))^(Theta)`

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To solve the problem, we need to calculate the equilibrium constant \( K_1 \) for the complexation reaction: \[ \text{Sr}^{2+} + \text{NO}_3^- \rightleftharpoons \text{Sr(NO}_3)_2^+ \] ### Step-by-Step Solution: ...
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