The number of `H^(o+)` ions present in `1mL` of solution having `pH = 13` is

Options

A. (a) `6.023 xx 10^(10)`
B. (b) `6.023 xx 10^(7)`
C. (c) `6.023 xx 10^(13)`
D. (d) `10^(13)`

Answer

B

Explanation

`pH = 13`
`[H^(o+)] = 10^(-13)M = 10^(-13) mol (1000 mL)^(-1)`
`= (10^(-13))/(1000) = 10^(-16) mol mL^(-1)`
Number of `[H^(o+)] = 10^(-16) xx 6.023 xx 10^(23)`
`= 6.023 xx 10^(7) ions`.