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A weak acid, HA, has a K(a) of 1.00xx10^...

A weak acid, HA, has a `K_(a)` of `1.00xx10^(-5)`. If `0.100` mol of the acid is dissolved in 1 L of water, the percentage of the acid dissociated at equilibrium is the close to

A

`0.1%`

B

`1.0%`

C

`99.0%`

D

`99.9%`

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha = sqrt((K_(a))/(c)) = sqrt((10^(-5))/(0.1)) = 10^(-2)`
`alpha% 10^(-2) xx 100 = 1%`
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