Which of the following solution have `pH gt 7`.
I. `BaF_(2)` II. `RbI`
III. `C_(6)H_(5)COONa`
IV. `(CH_(3)COO)_(2)Ba`

Options

A. `I`
B. `I,II, III`
C. `I,III`
D. `I,III,IV`

Explanation

To determine which of the given solutions have a pH greater than 7, we need to analyze each compound based on the nature of the acids and bases from which they are derived. Here’s the step-by-step solution:

### Step 1: Analyze BaF₂
- **Formation**: BaF₂ is formed from Ba(OH)₂ (barium hydroxide, a strong base) and HF (hydrofluoric acid, a weak acid).
- **Nature**: Since it is a salt of a strong base and a weak acid, the solution of BaF₂ will have a pH greater than 7.

### Step 2: Analyze RbI
- **Formation**: RbI is formed from RbOH (rubidium hydroxide, a strong base) and HI (hydroiodic acid, a strong acid).
- **Nature**: This salt is derived from a strong base and a strong acid, which means the solution will have a pH equal to 7.

### Step 3: Analyze C₆H₅COONa
- **Formation**: C₆H₅COONa (sodium benzoate) is formed from C₆H₅COOH (benzoic acid, a weak acid) and NaOH (sodium hydroxide, a strong base).
- **Nature**: This is a salt of a strong base and a weak acid, so the solution will have a pH greater than 7.

### Step 4: Analyze (CH₃COO)₂Ba
- **Formation**: (CH₃COO)₂Ba (barium acetate) is formed from CH₃COOH (acetic acid, a weak acid) and Ba(OH)₂ (barium hydroxide, a strong base).
- **Nature**: This is also a salt of a strong base and a weak acid, thus the solution will have a pH greater than 7.

### Conclusion
Based on the analysis:
- **BaF₂**: pH > 7 (strong base + weak acid)
- **RbI**: pH = 7 (strong base + strong acid)
- **C₆H₅COONa**: pH > 7 (strong base + weak acid)
- **(CH₃COO)₂Ba**: pH > 7 (strong base + weak acid)

Therefore, the solutions that have a pH greater than 7 are **I (BaF₂)**, **III (C₆H₅COONa)**, and **IV ((CH₃COO)₂Ba)**.

### Final Answer
The solutions with pH > 7 are: **I, III, and IV**.

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