The expression to calculate `pH` of sodium acetate solution at `25^(@)C` is

Options

A. `pH = 7 +(1)/(2)pK_(b) (CH_(3)COOH) - (1)/(2)log["salt"]`
B. `pH = 7+(1)/(2)pK_(a) (CH_(3)COOH) - (1)/(2)log ["salt"]`
C. `pH = 7+(1)/(2)pK_(b)(CH_(3)COOH) +(1)/(2) log ["salt"]`
D. `pH = 7 +(1)/(2) pK_(a)(CH_(3)COOH) +(1)/(2)log ["salt"]`

Answer

D

Explanation

`pH` of salt of `W_(A)//S_(B)` is
`pH = (1)/(2) (pK_(w) + pK_(a) + log C)`
`= (14)/(2) + (1)/(2) pK_(a) + (1)/(2) log C`
` = 7 + (1)/(2) pK_(a) (CH_(2)COOH) +(1)/(2) log["Salt"]`