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1.75g of solid NaOH is added to 0.25dm^(...

`1.75g` of solid `NaOH` is added to `0.25dm^(3)` of `0.1M NiCl_(2)` solution. Calculate:
a. Mass of `Ni(OH)_(2)` forms
b. `pH` if final solution Given `K_(sp)` of `Ni(OH)_(2) = 1.6 xx 10^(-14)`

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To solve the problem, we will break it down into two parts: calculating the mass of Ni(OH)₂ formed and then calculating the pH of the final solution. ### Part A: Mass of Ni(OH)₂ formed 1. **Calculate moles of NaOH:** - Given mass of NaOH = 1.75 g - Molar mass of NaOH = 40 g/mol \[ ...
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