calculate the number of electrons which will together weigh one gram.
(ii) calculate the mass and charge of one mole of electrons .

Explanation

`9.11xx10^(-28) g` is the mass of `1` electron `1 g` is the mass of
`(1xx1)/(9.11xx10^(-28))=(10xx27)/(9.11)=1.099xx10^(27)`
b. Mass of `1` electron `=9.1xx10^(-31)kg`
Mass of `6.023xx10^(23)` electrons
`=6.023xx10^(23)xx9.1xx10^(-31) kg`
`=5.48xx10^(-7)kg`
Charge of one electron `=1.6xx10^(-19)` coulomb
Charge of `6.023xx10^(23)` electrons
`=6.023xx10^(23)xx1.6xx10^(-19)`
`=9.65xx10^(4)C`