calculte the total number of electrons present 1.4 g of dinitrogen gas.

Explanation

`28 g` of nitrogen gas `=1 mol=14 mol e^(-)`
(Atomic weight of `N=7`. Number of `e^(-)` in `N_(2)=14)`
`1.4 g` of nitrogen `=1.4/28=1/20 mol`
`1 mol` of `N_(2)` contains `=6.022xx10^(23)xx14e^(-)`
`1/20 mol` of `N_(2)` contains `=(6.022xx10^(23)xx14)/(20)`
`=4.2161xx10^(23)` electrons