Find out of the value of `K_(c)` for each of the following equilibrium from the value of `K_(p)`:
(i) `2NOCl (g) hArr 2NO(g) + Cl_(2)(g), K_(p) = 1.8 xx 10^(-2)` at `500 K`
(ii) `CaCO_(3) (s) hArr CaO(s) + CO_(2)(g), K_(p) = 167` at `1073 K`

Explanation

a. `Deltan_(g)=3-2=1`,
`K_(p)=K_(c )(RT)` or `K_(c )==K_(p)/(RT)=(1.8xx10^(-2))/(0.0831xx500)`
`=4.33xx10^(-4), (R=0.0831 "bar" L mol^(-1) K^(-1))`
b. `Deltan_(g)=1-0=1`,
`K_(c )=K_(p)/(RT)=167/(0.0831xx1073)=1.87`