Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as :
` CH_3COOH(l) +C_2H_5OH(l) hArr CH_3COOC_2H_5(l) +H_2O(l)`
Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime . Has equilibrium been reached?

Explanation

a. `Q_(C )=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([CH_(3)COOH][C_(2)H_(5)OH])`
b. `CH_(3)COOH+C_(2)H_(5)OH hArr CH_(3)COOC_(2)H_(5)+H_(2)O`
`{:(1.00 mol,0.180 mol,,,"Initial"),(1-0.171,0.180-0.171,,0.171 mol,0.171 mol),(=0.829,=0.009,,,"At equilibrium"),(mol,mol,,,),(0.829//V,0.009//V,,0.171//V,0.171//V),(,,,,"Molar concentration"):}`
`K_(c )=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([CH_(3)COOH][C_(2)H_(5)OH])`
`=((0.171//V)(0.171//V))/((0.829//V)(0.009//V))=3.92`
c. `CH_(3)COOH+C_(2)H_(5)OH hArr CH_(3)COOC_(2)H_(5)+H_(2)O`
`{:(1.000 mol,0.500 mol,,,Initial),(1-0.214,0.500-0.214,,0.214,0.214),(=0.786,=0.286,,mol,mol),(mol,mol,,,"After time t"):}`
Reaction quotient `(Q_(c ))=((0.214//V)(0.214//V))/((0.786//V)(0.286//V))`
`=0.204`
As `Q_(c )ne K_(c )`, equilibrium has not been attained.