Home
Class 12
CHEMISTRY
Calculate the value of Avogadro's number...

Calculate the value of Avogadro's number from the following data:
Density of `NaCl = 2.165 g cm^(-3)`
Distance between `Na^(o+)` and `Cl^(Θ)` in `NaCl = 281` pm

Text Solution

AI Generated Solution

To calculate Avogadro's number (Na) using the given data, we can follow these steps: ### Step 1: Understand the Formula The formula relating density (d), molar mass (M), Avogadro's number (Na), and the unit cell volume (a^3) is given by: \[ d = \frac{Z \cdot M}{N_a \cdot a^3} \] ...
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|13 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|13 Videos
  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise SUBJECTIVE TYPE|4 Videos
  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 2.3 (Objective)|9 Videos

Similar Questions

Explore conceptually related problems

Calculate the value of Avogadro number from the internuclear distance of adjacent ions in NaCl, 0.282 nm and the density of solid NaCl is 2.17xx10^(3)kg//m^(3) . A unit cell contains 4 NaCl formula units.

CsCl has cubic structure. Its density is 3.99 g cm^(-3) . What is the distance between Cs^(o+) and Cl^(Θ) ions? (Atomic mass of Cs = 133 )

Sodium chloride crystallizes in face-centred cubic (f.c.c.) structure. Its density is 2.165 g cm^(-3) . If the distance between Na^+ and its nearest Cl^(-) ions is 281 pm, find out the Avogadro's number (Na = 23 g "mol"^(-), Cl = 35.5 g "mol"^(-) ).

What is the molality of a semimolar NaCl solution if the density of the solution is 1.16 g cm^(-3) ?

The density of NH_(4)Cl is 1.534 g cm^(-3) . It crystallizes in the CsCl lattice. a. Calculate the length of the length of the edge of NH_(4)Cl unit cell. b. Calculate the shortest distance between a NH_(4)^(o+) ion and a Cl^(ɵ) ion. c. Calculate the radius of NH_(4)^(o+) ion if the radius of the Cl^(ɵ) ion is 181 pm

The distance between Na^+ and Cl^- ions in NaCl with a density 3.165 g cm^(-3) is

The edge length of NaCl unit cell is 564 pm. What is the density of NaCl in g/ cm^(3) ?

The distance between Na^(+) and Cl^(-) ion ion NaCI is 281 pm. What is the edge length of the cube

Calculate the number of formula units of NaCl per unit cell of NaCl. Given : (i)Internuclear distance of adjacent ions = 0.282 nm (ii)Density of solid NaCl= 2.17xx10^3 "kg/m"^3

KF has NaCl structure. What is the distance between K^(+) and F^(-) in KF, if the density is 1.5g cm^(-3) ?