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CsBr crystallizes in a body-centred cubi...

`CsBr` crystallizes in a body-centred cubic unit lattice with an edge length of `4.287 Å`. Calculate the angles at which the second-order reflection maxima may be expected for `(2, 0, 0)`, `(1, 1, 0)`, planes when `X`-rays of `gamma = 0.50 Å` are used.

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To solve the problem of calculating the angles at which the second-order reflection maxima may be expected for the (2, 0, 0) and (1, 1, 0) planes in a body-centered cubic (BCC) lattice of CsBr, we will follow these steps: ### Step 1: Calculate the interplanar spacing (d) for the (2, 0, 0) planes The formula for interplanar spacing \( d \) for a cubic lattice is given by: \[ d = \frac{a}{\sqrt{h^2 + k^2 + l^2}} ...
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