If `NaCl` is doped with `10^(-3) mol% GaCl_(3)`, what is the concentration of the cation vacancies?

Explanation

To find the concentration of cation vacancies in NaCl doped with \(10^{-3}\) mol% GaCl\(_3\), we can follow these steps:

### Step 1: Understand the Doping Process
When NaCl is doped with GaCl\(_3\), Ga\(^3+\) ions replace some of the Na\(^+\) ions. Each Ga\(^3+\) ion will create cation vacancies because it has a higher charge than Na\(^+\).

### Step 2: Calculate the Moles of GaCl\(_3\)
Given that the doping concentration is \(10^{-3}\) mol%, we need to convert this to moles.

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