Home
Class 12
CHEMISTRY
Cesium chloride forms a body-centred cub...

Cesium chloride forms a body-centred cubic lattice. Cesiumm and chloride ions are in contact along the body diagoanl of a cell. The length of the side of the unit cell is `412 pm` and `Cl^(Θ)` ion has a radius of `181` pm. Calculate the radius of `Cs^(o+)` ion.

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the radius of the cesium ion (Cs⁺) in a cesium chloride (CsCl) body-centered cubic (BCC) lattice, given the radius of the chloride ion (Cl⁻) and the side length of the unit cell. ### Step-by-Step Solution: 1. **Understand the BCC Structure**: - In a body-centered cubic (BCC) lattice, the chloride ions (Cl⁻) are located at the corners of the cube, and the cesium ions (Cs⁺) are located at the body center of the cube. 2. **Identify the Given Values**: ...
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|13 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Multiple Correct)|39 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos

  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise SUBJECTIVE TYPE|4 Videos

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 2.3 (Objective)|9 Videos

Similar Questions

Explore conceptually related problems

Caesium and chloride ions are in contact along the body diagonal in a body-centred cubic lattice. The edge lenth of the unit cell is 350 pm and Cs^+ has a radius of 133pm. Hence, the radius of Cl^- ion is approximately

Potassium chloride crystallize with a body-centred cubic lattice. Calculate the distance between the 200, 110, and 222 Planes. The length of the side of the unit cell is 5.34 Å .

Lithium forms body centred cubic structure. The length of the side of its unit cell is 351 pm. Atomic radius of the lithium will be

A solid A^(+)B^(-) has a body centred cubic structure. The distance of closest approach between the two ions is 0.767Å .The edge length of the unit cell is

If the edge-length of the unit cell of sodium chloride is 600 pm, and the ionic radius of CI^(-) ion is 190 pm, then the ionic radius of Na^(+) ion is

Lithium forms body centred cubic structure .The length of the side of its unit cells is 351 pm.A tomic radius of lithium will be :

Lithium forms body centred cube structure .The length of the side of its unirt cell is 310 pm Atomic radius of the lithium will be

Lithium forms body centred cube structure .The length of the side of its unirt cell is 325 pm Atomic radius of the lithium will be

In the distance between Na^(+) and CI^(-) ions in sodium chloride crystal is y pm , the length of the edge of the unit cell is

A solid AB has ZnS-type structure. The edge lenth of unit cell is 400 pm abd the radius of 'B^-' ion is 0.130 nm. Then the radius of 'A^+' ion is