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In the cubic crystal of CsCl (d = 3.97 g...

In the cubic crystal of `CsCl (d = 3.97 g cm^(-3))`, the eight corners are occupied by `Cl^(Θ)` with a `Cs^(o+)` at the centre and vice versa. Calculate the distance between the neighbouring `Cs^(o+)` and `Cl^(Θ)` ions. What is the radius of the two ions? (`Aw` of `Cs = 132.91` and `Cl = 35.45)`

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To solve the problem step by step, we will follow the instructions given in the video transcript and apply the relevant formulas. ### Step 1: Write down the given data - Density of CsCl, \( d = 3.97 \, \text{g/cm}^3 \) - Atomic weight of Cs, \( A_{Cs} = 132.91 \, \text{g/mol} \) - Atomic weight of Cl, \( A_{Cl} = 35.45 \, \text{g/mol} \) ### Step 2: Calculate the molar mass of CsCl ...
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