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Li forms a body-centred cubic lattice. I...

`Li` forms a body-centred cubic lattice. If the edge of the cube is `3.5 xx 10^(-10)m` and the density is `5.3 xx 10^(2) kg m^(-3)`, calculate the percentage occupancy of `Li` metal.

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To solve the problem, we need to calculate the percentage occupancy of lithium (Li) in a body-centered cubic (BCC) lattice given the edge length of the cube and the density of lithium. ### Step-by-Step Solution: 1. **Identify the given data:** - Edge length of the cube (a) = \(3.5 \times 10^{-10} \, \text{m}\) - Density (D) = \(5.3 \times 10^{2} \, \text{kg/m}^3\) - Molar mass of lithium (Li) = \(7 \, \text{g/mol} = 7 \times 10^{-3} \, \text{kg/mol}\) ...
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