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The ratio of packing fraction in fcc, bc...

The ratio of packing fraction in fcc, bcc, and cubic structure is, respectively,

A

`1: 0.92: 0.70`

B

`0.70: 0.92: 1`

C

`1: 0.70: 0.92`

D

`0.92: 0.70: 1`

Text Solution

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The correct Answer is:
To find the ratio of packing fractions in FCC (Face-Centered Cubic), BCC (Body-Centered Cubic), and simple cubic structures, we will follow these steps: ### Step 1: Understand the Packing Fraction Formula The packing fraction (PF) is defined as the fraction of volume in a crystal structure that is occupied by the constituent particles (atoms, ions, or molecules). The formula for packing fraction is given by: \[ \text{Packing Fraction} = \frac{Z \cdot \frac{4}{3} \pi r^3}{a^3} \] Where: - \(Z\) = number of atoms per unit cell - \(r\) = radius of the atom - \(a\) = edge length of the unit cell ### Step 2: Calculate Packing Fraction for FCC In FCC: - \(Z = 4\) (4 atoms per unit cell) - The relationship between the radius \(r\) and the edge length \(a\) is given by \(a = 2\sqrt{2}r\). Substituting this into the packing fraction formula: \[ \text{Packing Fraction}_{FCC} = \frac{4 \cdot \frac{4}{3} \pi r^3}{(2\sqrt{2}r)^3} \] Calculating the denominator: \[ (2\sqrt{2}r)^3 = 8 \cdot 2\sqrt{2}^3 \cdot r^3 = 16\sqrt{2}r^3 \] So, \[ \text{Packing Fraction}_{FCC} = \frac{4 \cdot \frac{4}{3} \pi r^3}{16\sqrt{2}r^3} = \frac{16\pi}{48\sqrt{2}} \approx 0.74 \] ### Step 3: Calculate Packing Fraction for BCC In BCC: - \(Z = 2\) (2 atoms per unit cell) - The relationship between \(r\) and \(a\) is \(a = \frac{4r}{\sqrt{3}}\). Substituting into the packing fraction formula: \[ \text{Packing Fraction}_{BCC} = \frac{2 \cdot \frac{4}{3} \pi r^3}{\left(\frac{4r}{\sqrt{3}}\right)^3} \] Calculating the denominator: \[ \left(\frac{4r}{\sqrt{3}}\right)^3 = \frac{64r^3}{3\sqrt{3}} \] So, \[ \text{Packing Fraction}_{BCC} = \frac{2 \cdot \frac{4}{3} \pi r^3}{\frac{64r^3}{3\sqrt{3}}} = \frac{8\pi\sqrt{3}}{64} \approx 0.68 \] ### Step 4: Calculate Packing Fraction for Simple Cubic In simple cubic: - \(Z = 1\) (1 atom per unit cell) - The relationship between \(r\) and \(a\) is \(a = 2r\). Substituting into the packing fraction formula: \[ \text{Packing Fraction}_{Cubic} = \frac{1 \cdot \frac{4}{3} \pi r^3}{(2r)^3} \] Calculating the denominator: \[ (2r)^3 = 8r^3 \] So, \[ \text{Packing Fraction}_{Cubic} = \frac{\frac{4}{3} \pi r^3}{8r^3} = \frac{\pi}{6} \approx 0.52 \] ### Step 5: Calculate the Ratio of Packing Fractions Now we have: - Packing Fraction in FCC = 0.74 - Packing Fraction in BCC = 0.68 - Packing Fraction in Cubic = 0.52 To find the ratio, we can express it as: \[ \text{Ratio} = \text{Packing Fraction}_{FCC} : \text{Packing Fraction}_{BCC} : \text{Packing Fraction}_{Cubic} = 0.74 : 0.68 : 0.52 \] To simplify, we divide each term by 0.52: \[ \text{Ratio} = \frac{0.74}{0.52} : \frac{0.68}{0.52} : \frac{0.52}{0.52} \approx 1.42 : 1.31 : 1 \] This can be approximated to: \[ 1 : 0.92 : 0.70 \] ### Final Answer Thus, the ratio of packing fractions in FCC, BCC, and simple cubic structures is: \[ \text{Answer: } 1 : 0.92 : 0.70 \]

To find the ratio of packing fractions in FCC (Face-Centered Cubic), BCC (Body-Centered Cubic), and simple cubic structures, we will follow these steps: ### Step 1: Understand the Packing Fraction Formula The packing fraction (PF) is defined as the fraction of volume in a crystal structure that is occupied by the constituent particles (atoms, ions, or molecules). The formula for packing fraction is given by: \[ \text{Packing Fraction} = \frac{Z \cdot \frac{4}{3} \pi r^3}{a^3} \] ...
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